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this is if first choice is g1 which has ten ways now for b1 also there willbe 10 ways.
rohit pandeyQuote 
got the above questions
another question
n people are seated in random manner in a row containing 2n seats ,what is probability that no two people will occupy adjacent seats.
rohit pandeyQuote 

if we take m=1 and n=5 it is not divisble by 5 so we cant generalize m and nas odd will always yield numbers divisible by 5 .
rohit pandeyQuote 
shruti the answer for q2 is indeed 20 but i will have to explain it in class.hint try forming a tree its really big.
and for q1 if you take and sum the different permutations of 7 numbers form set you will find the sum of 4 options is divisible by 9 hence 4*7!.
rohit pandeyQuote 

just one correction p(a)=60c10/90c10
and p(a∩b)=30c10/90c10so p(aubuc)=3*{60C1030C10}/90C10
sorry had misplaced the values as i was sleepy
and p(aubuc) covers the possibility of two balls not being selected.
rohit pandeyQuote 
take three events
A={NO RED BALL}
B={NO BLUE BALL}
C={NO WHITE BALL}
SO WE NEED TO FIND P{AUBUC}=?SO P(A)=30C10/90C10 P(B) AND P(C) WILL BE SAME
NOW P(A∩B)=60C10/90C10 P(B∩c) and p(A∩C) WIL BE SAMENOW P(A∩B∩C)=0 {CANT HAPPEN}
SO P(AUBUC}=3*{30C1060C10}/90C10
rohit pandeyQuote 
the answer is {6*7!/2!}/6^7
realised the above answer is wrong
first there are 7! ways for dice to get numbers since two numbers are same so divide by 2! and since there are six numbers that will be repeated there are 6 cases so multiply it by 6
rohit pandeyQuote 
for q 1
even digits are 0 , 2 , 4 ,6 ,8
so probable 4 digits are 1.0246=0+2+4+6=12
2.2468=2+4+6+8=20
3.4680=4+6+8+0=18
4.6802=6+8+0+2=16
5.8024=8+0+2+4=14only option 1 and option 3 is divisible by 3
so permutation of option1=4!3!
( we do 3! factorial because we need 4 digit numbers and thus we fix 0 at fourth place and form permutations and subtract it from total permutations}
and
permutation of option2=4!3! {same thing again}
this is a probable answerwhere did you get this question?
rohit pandeyQuote 
for q2
at least 2 digits same means
we take cases for
1.2 same digits
2.3 same digits
3.4 same digitsand add them up
for case 15*4*3*2/2!
for case 2 – 5*4*3*2/3!
for case 3 – 5*4*3*2/4!
now add all of them up
this is a probable solution
rohit pandeyQuote 
there are 7 different dices _ _ _ _ _ _ _
for 1st dice it can take any 6 numbers but other 6 dices will have permutation of 6*5*4*3*2*1*6
total no of events =6^7so probability=6*5*4*3*2*1*6/6^7
maybe right maybe wrong
rohit pandeyQuote 

dont confuse yourself with variables at first just follow the question and calculate coordinates for 5000$ on boring business magazine and trendy consumer magazine.
the question is about plotting points on graph and the calculate slope using yy1=m(xx1)
where m is slope m=y2y1/x2x1.
lawyer mba
5000$ on business mag(3000 , 10000)(x1,y1)
5000$ on consumer mag(5000 , 6000 )(x2,y2)so y10000/x3000=4000/2000
so the budget line is y+2x=16000
where y=M and x=L
rohit pandeyQuote 
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